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tools/接口/N等分点.ms
2025-07-31 16:05:55 +08:00

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nums=3
b=$Point001
c=$Point002
a=#()
a[1]=b
for i=1 to (nums-1) do
(
a[i+1]=point()
a[i+1].pos=(i*c.pos+(nums-i)*b.pos)/nums
)
a[nums+1]=c